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信息发布者:
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证明:
$\because EF⊥ AB,$$CD⊥ AB$(已知),
$\therefore EF// CD$(在同一平面内,垂直于同一条直线的两条直线平行),
$\therefore ∠ BEF=∠ BCD$(两直线平行,同位角相等),
$\because ∠ B=∠ BEF$(已知),
$\therefore ∠ B=∠ BCD$(等量代换),
又$\because ∠ DGA=∠ BCA$(已知),
$\therefore DG// BC$(同位角相等,两直线平行),
$\therefore ∠ ADG=∠ B,$$∠ GDC=∠ BCD$(两直线平行,同位角相等,内错角相等),
$\therefore ∠ ADG=∠ GDC$(等量代换),
$\therefore DG$平分$∠ ADC$(角平分线的定义)。
(1) 证明:
$\because a > b,$$a,b$为正数,
$\therefore a - b > 0,$$a + b > 0,$
$\therefore a^2 - b^2 = (a + b)(a - b) > 0,$
$\therefore a^2 > b^2。$
(2) 证明:
$\because a^2 > b^2,$
$\therefore a^2 - b^2 = (a + b)(a - b) > 0,$
$\because a,b$为正数,
$\therefore a + b > 0,$
$\therefore a - b > 0,$
$\therefore a > b。$