电子课本网 第77页

第77页

信息发布者:
$-\frac{1}{5}$
解:$4x + 6 = 5$
$4x = 5 - 6$
$4x = -1$
$x = -\frac{1}{4}$
解:$x + 3 = 5x - 1$
$x - 5x = -1 - 3$
$-4x = -4$
$x = 1$
解:$\frac{1}{2}y + 2 = 3y - \frac{5}{2}$
$y + 4 = 6y - 5$(两边同时乘以2)
$y - 6y = -5 - 4$
$-5y = -9$
$y = \frac{9}{5}$
解:$1 = \frac{x}{2} - 5$
$2 = x - 10$(两边同时乘以2)
$x = 12$
解:​$(1)$​由题意得​$2x + 3 = -5x + 2$​
​$ 2x + 5x = 2 - 3$​
​$ 7x = -1$​
​$ x = -\frac {1}{7}$​
解:​$(2)$​由题意得​$2x + 3 + (-5x + 2) = 0$​
​$ 2x + 3 - 5x + 2 = 0$​
​$ -3x + 5 = 0$​
​$ -3x = -5$​
​$ x = \frac {5}{3}$​

$\frac{1}{2}$
解:​$(1)$​因为​$x = -2$​是方程​$2a + 4x = x + 5a$​的解,
所以将​$x=-2$​代入方程得:
​$ 2a + 4×(-2) = -2 + 5a$​
​$ 2a - 8 = -2 + 5a$​
​$ 2a - 5a = -2 + 8$​
​$ -3a = 6$​
​$ a = -2$​
​$ (2)$​由​$(1)$​知​$a=-2,$​将其代入方程​$ay + 5 = 6a - y$​得:
​$ -2y + 5 = 6×(-2) - y$​
​$ -2y + 5 = -12 - y$​
​$ -2y + y = -12 - 5$​
​$ -y = -17$​
​$ y = 17$​