第86页

信息发布者:
(1)电流$I=\frac{U_{2}}{R_{2}}=\frac{6\ \text{V}}{60\ \Omega}=0.1\ \text{A};$
(2)$R_{1}$两端电压$8\ \text{V}-6\ \text{V}=2\ \text{V},$$R_{1}=\frac{2\ \text{V}}{0.1\ \text{A}}=20\ \Omega;$
(3)电流0.2 A时,总电阻$R_{\text{总}}=\frac{8\ \text{V}}{0.2\ \text{A}}=40\ \Omega,$$R_{2}=40\ \Omega-20\ \Omega=20\ \Omega,$电压表示数$U=0.2\ \text{A}\times20\ \Omega=4\ \text{V}。$
(1)最大电流15 mA=0.015 A,$U_{0}=IR_{0}=0.015\ \text{A}\times400\ \Omega=6\ \text{V};$
(2)由数据得$R=300 - 0.4F;$
(3)当$R=0$时,$0=300-0.4F,$$F=750\ \text{N},$但电源电压7.5 V,$I=\frac{7.5\ \text{V}}{400\ \Omega}=0.01875\ \text{A}>0.015\ \text{A},$所以最大$F=500\ \text{N},$量程0~500 N;
(4)串联电阻或减小电源电压。