第26页

信息发布者:
-78
$ 解:设20182019=b,那么x=(b-1)(b+3)-(b+2)b=-3$
$y=b(b+4)-(b+1)(b+3)=-3,所以x=y$
$解:(1)∵n为正整数,x^{2n}=3,∴x^{n-3}×x^{3(n+1)}=x^{n-3}×x^{3n+3}=(x^{2n})^{2}=9$
$(2)5(x^{3n})^{2}-2(-x^{2})^{2n}=5x^{6n}-2x^{4n}=5(x^{2n})^{3}-2(x^{2n})^{2}=117$