第27页

信息发布者:
$解:原式=-1-(-3)×\frac 13$
$\ \ \ \ \ \ \ \ =-1-(-1)$
$\ \ \ \ \ \ \ \ =0$
$解:原式=-1-4+8+6$
$\ \ \ \ \ \ \ =-5+14$
$\ \ \ \ \ \ \ =9$
$解:根据题意可得:x+4=0,y-\frac{1}{2}=0$
$∴x=-4,y=\frac{1}{2}$
$原式=3x²-6xy-2(\frac{1}{4}xy-1-\frac{3}{2}xy+\frac{3}{2}x²)$
$=3x²-6xy-\frac{1}{2}xy+2+3xy-3x²$
$=2-\frac{7}{2}xy$
$=2-\frac{7}{2}×(-4)×\frac{1}{2}$
$=9$
$解:12-3(4-3x)=2(5x+3)-12x$
$\ \ \ \ \ 12-12+9x=10x+6-12x$
$\ \ \ \ \ \ \ \ \ \ \ \ \ 11x=6$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\frac {6}{11}$
$解:2x-6=3x+12$
$\ \ \ \ \ \ -x=18$
$\ \ \ \ \ \ \ x=-18$