$ 解:原式 = (1-\frac{1}{2})× (1+\frac{1}{2})× (1-\frac{1}{3})× (1+\frac{1}{3})$
$~~~~~~~~~~~~~~~~~~~×(1-\frac{1}{4})×(1+\frac{1}{4})×···×(1-\frac{1}{2024})$
$~~~~~~~~~~~~~~~~~~~×(1+\frac{1}{2024}) $
$~~~~~~~~~~~~~~~~~~=\frac{1}{2}×(\frac{3}{2}×\frac{2}{3})× (\frac{4}{3}×\frac{3}{4})$
$~~~~~~~~~~~~~~~~~~~×···×(\frac{2024}{2023}×\frac{2023}{2024})×\frac{2025}{2024} $
$~~~~~~~~~~~~~~~~~~=\frac{1}{2}×\frac{2025}{2024} $
$~~~~~~~~~~~~~~~~~~=\frac{2025}{4048} $