第133页 - 经纶学典新课时作业八年级数学上下册【江苏国标】

$\frac{2\sqrt{3}}{5}$

$\sqrt{7}$

$ \begin{aligned}解:原式&=4\sqrt{6÷2} \\ &=4\sqrt{3} \\ \end{aligned}$

$ \begin{aligned}解:原式&=\frac {\sqrt{3}×\sqrt{7}×\sqrt{5}×\sqrt{7}}{\sqrt{3}×\sqrt{5}} \\ &=7 \\ \end{aligned}$

$ \begin{aligned}解:原式&=\sqrt{\frac {ab}{15}×\frac {27a^3}{5b}} \\ &=\sqrt{\frac {9a^4}{25}} \\ &=\frac {3}{5}a^2 \\ \end{aligned}$

$ \begin{aligned} 解:原式&=\frac {\sqrt{0.04}×\sqrt{144}}{\sqrt{0.36}×\sqrt{121}} \\ &=\frac {0.2×12}{0.6×11} \\ &=\frac {4}{11} \\ \end{aligned}$

（更多请点击查看作业精灵详解）

$ \begin{aligned}解:原式&=-\frac {2}{3}÷2×\sqrt{30÷\frac {3}{5}} \\ &=-\frac {1}{3}×\sqrt{50} \\ &=-\frac {5\sqrt{2}}{3} \\ \end{aligned}$

$ \begin{aligned} 解:原式&=\sqrt{\frac {676}{625}-\frac {4}{25}} \\ &=\sqrt{\frac {576}{625}} \\ &=\frac {24}{25} \\ \end{aligned}$

$ \begin{aligned}解:原式&=\sqrt{\frac {13}{16^2}} \\ &=\frac {\sqrt{13}}{16} \\ \end{aligned}$

$ \begin{aligned}解:原式&=\sqrt{\frac {(-3)×8}{-3(a^2-4a+4)}}(a＞2) \\ &=\sqrt{\frac {8}{a^2-4a+4}} \\ &=\sqrt{\frac {4×2}{(a-2)^2}} \\ &=\frac {2\sqrt{2}}{a-2} \\ \end{aligned}$

$ \begin{aligned} 解:∵ \frac{a}{b} &= \sqrt{\frac{2022}{2023}} ÷\sqrt{\frac{2023}{2024}} \\ &=\sqrt{\frac{2022}{2023}÷\frac{2023}{2024}} \\ &= \sqrt{\frac{2022}{2023}×\frac{2024}{2023}} \\ &=\sqrt{\frac{(2023-1)×(2023+1)}{2023²}} \\ &= \sqrt{\frac{2023²-1}{2023²}}＜1， \\ \end{aligned}$

$∴a＜b.$